Problem Set2(Digit in a factor)

Problem Set2

Digits in a factor

Q. Given a number ‘n’, design an algorithm and write the Python program to  print the digits of ‘n’ that  divides ‘n’. Print the digits in reverse order of their appearance in the number ‘n’.  For example, if n is 122 then print 2, 2, 1. Use only conditional and iterative statements to write the code. If none of the digits divide the number, then print ‘No factors’

Input Format

A number, n 

Output Format

Digits in the number ‘n’ that divides ‘n’ in reverse order

Input:

Get the input number and store it in num1

Processing:

let temp = num1

let temp1 = 0

let count = 0

while temp!=0

  temp1 = temp%10

  if num1%temp1 == 0

   print(temp1)

   count+=1

Output:

Print the factors of the number in the reverse order if any else display no factors.

Algorithm:

Step1. Get the number and store it in variable n.

Step2. Assign count as 0 and let copy as n.

Step3. Repeat till copy is not equal to zero

Step3.1 Let temp as copy%10

Step3.2 if  the remainder obtained when n is divided by temp is zero

Step3.2.1 if true display temp and increment count by 1 

Step4. if count is equal to zero then display no factor

Step5. End

Flowchart:

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Program:

n=int(input())

temp = n

count = 0

length = len(str(n))

for i in range(length):

 factor=temp%10

 if(n%factor==0):

  print(factor)
  count+=1

 temp=temp//10

if(count==0):

    print('No factors')